posted                      

quote:

---

Brainstorm..

---

Sounds painful

--------------------
*Coming soon: Something so awesome to look at it will make your eyeballs explode*

Posts: 6460 (0.98 per day) | From: Hadleys Hope | Registered: Jun 2001 (6542 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Phoenix:
I want that book as well where you get your answers Gemini

---

Posts: 59 (0.01 per day) | From: Belgium | Registered: Apr 2003 (5870 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Gemini:

quote:

---

Originally posted by Sigos_Phoenix:
I want that book as well where you get your answers Gemini

---

you have just to find two interger > 0, a and b witch solve the equation a²=113 b² -1. i have generate with microsoft exel, a column with the possible value of b (1,2,3....), a second column with the correspondant value of the right member of the equation (113 b² -1 for b=1,2,...) and a third one with the square root of the last column. i have choosen the value of b for witch the last column is an interger.

---

very nice

--------------------
ZN: Sigos_Taurus_

Posts: 227 (0.03 per day) | From: surrey, england | Registered: Apr 2003 (5869 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Gemini:

quote:

---

Originally posted by Sigos_Phoenix:
I want that book as well where you get your answers Gemini

---

you have just to find two interger > 0, a and b witch solve the equation a²=113 b² -1. i have generate with microsoft exel, a column with the possible value of b (1,2,3....), a second column with the correspondant value of the right member of the equation (113 b² -1 for b=1,2,...) and a third one with the square root of the last column. i have choosen the value of b for witch the last column is an interger.

---

OMG GEM, u r genius

--------------------

Posts: 394 (0.06 per day) | From: Somewhere in Tundra | Registered: Jan 2003 (5949 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Libra:
Heres one that dont need so much mathematics...

A King wanted to have some fun and put three prisoners to a test.
King took 3 hats from box, where were 5 hats - 3 red and 2 white hats.
King put hat to every prisoner and left those two extra hats to box.
He told prisoners, that there were originally 3 reds and 2 white hats.
Then King said, that prisoners should conclude their hat colour.
King also said, that he, who first can tell colour of his hat (and tells why hat is that colour) is free to go.
First prisoner looked at other two and said: " i dont know"
Second prisoner looked other two and said: "i dont know"
Third prisoner, who was blind, was also smart. So he said colour of his hat after few minutes.
What colour was his hat (and why)??

---

Well this i will answer cause there is only 2 choices
and i say blind got red hat? i cant wait correct answer so i will call u.....

--------------------

Posts: 394 (0.06 per day) | From: Somewhere in Tundra | Registered: Jan 2003 (5949 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Libra:
This is LITTLE harder, lol!

Famous mathematician G.D.Hardy was visiting hes sick friend, almost as famous colleague from India, Ramanujan and said, that taxitrip costed 1729 pounds. Stupid number, he said.
Not at all, said Ramanujan, because thats smallest number that can be written with sum of two numbers raised to the third power in two different ways: (i dont know how, or is it even possible to get those little numbers, but i put them in parentheses...) 1(3)+12(3)=9(3)+10(3)=1729.
So...now YOUR task is to find 4 positive numberswith sum of 42. And when these numbers are raised to third power, sum of two are same as sum of other two...

Have fun (Gemini)! LOL

---

arg that will be hard to solve this with ecxel. maybe with a little short program but i haven't any language environment install on my computer (and i don't know how to use one with windows)

Posts: 59 (0.01 per day) | From: Belgium | Registered: Apr 2003 (5870 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Libra:
And heres little iq-test...

5, 11, 23, __, 95, 191

What number is missing from middle?

---

Posts: 59 (0.01 per day) | From: Belgium | Registered: Apr 2003 (5870 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Gemini:

quote:

---

Originally posted by Sigos_Libra:
And heres little iq-test...

5, 11, 23, __, 95, 191

What number is missing from middle?

---

47

---

yeh this was easy, and they are best ones

--------------------

Posts: 394 (0.06 per day) | From: Somewhere in Tundra | Registered: Jan 2003 (5949 days)  |  IP: Logged | 

posted                      

quote:

---

Originally posted by Sigos_Libra:
Heres good one...


There was a thief at marketplace in Athena. Hes loot was so big, that he needed a cart to transver those things.
Sokrates interrogated four suspects, witch one was guilty.
Everyone of suspects gave four statements.
None of them spoke completely thruth, and there wasnt two, that would´ve have same amount of true statements.
Who was thief?


A:s statements:

1. D were at the marketplace many times.
2. We are all innocent.
3. B is stranger, and have been seen at the marketplace
4. My statements are all lie.


B:s statements:

1. A is innocent.
2. D owns a cart.
3. i have never even been at the marketplace.
4. D is stranger but hes been here many times.


C:s statements:

1. A:s 1. and 3. statement is lie.
2. D dont have a cart.
3.D is actually first time in Athena.
4. B:s statements are all true.


D:s statements:

1. I dont have a cart.
2. B is guilty.
3. This is first time that i´m in Athena.
4.B:s 3. statement is true.


Have a nice Brainstorm...i dont think its very hard, but it needs to focus...

---

i had enough this kind of category riddles, already when those prisoners did wear stupid white or red hats.


--------------------

Posts: 394 (0.06 per day) | From: Somewhere in Tundra | Registered: Jan 2003 (5949 days)  |  IP: Logged |